Charges Moving in Electric Fields
In a uniform field a charge feels the same force everywhere, so it accelerates steadily. That's just projectile motion with replaced by , and it's how oscilloscopes aimed their electron beams and how inkjet coders steer charged drops of ink.
What the symbols mean
- Acceleration
Constant in a uniform field: along E for positive charges, against it for negative ones.
- Charge
With its sign. An electron has q = −e.
- Mass
An electron's is 9.11 × 10⁻³¹ kg, so e/m = 1.76 × 10¹¹ C/kg: enormous accelerations.
What the symbols mean
- Charge per area on each plate
+σ on one plate and −σ on the other. Each makes σ/2ε₀; between the plates the two fields add, outside they cancel.
What the symbols mean
- Entry speed
Parallel to the plates. The field never changes this component.
- Plate length
The time between the plates is L/v₀.
- Exit angle
The direction of the velocity as the charge leaves the plates. Past them it flies straight.
What the symbols mean
- Work done by the field
All of it becomes kinetic energy.
- Displacement
Only its component along E counts: that's the dot product.
Explanation
A uniform field is simply one that has the same strength and direction everywhere in a region, like the field between two big charged plates; "uniform" just means it doesn't change from place to place. It's what lets oscilloscopes, inkjet coders and particle accelerators steer charges predictably. All we're really saying here is that a charge in such a field moves just like a ball thrown through the air, with the field doing the job gravity usually does. The formula is only three pieces: (how much charge, which sets how hard it's pushed), (the field, which sets the direction) and (the mass, since heavier things are harder to speed up). Push divided by mass gives acceleration, which is Newton's second law and nothing new. If you've done projectile problems, you already know most of this lesson.
A uniform field. Two large plates carry charge densities and . As you found in Fields of Continuous Charge, each makes a field of , away from the positive plate and toward the negative one. Between the plates both point the same way and add to ; outside they cancel. So in the gap the field is the same everywhere. With a voltage across a gap , it's (the volt arrives in Electric Potential).
Constant force, constant acceleration. The force is the same at every point, so is constant. And it can be huge. For an electron C/kg, so a modest 1 kN/C field gives m/s², more than times . So you can ignore gravity for electrons and ions. For charged dust and ink drops, which are far heavier, compare with first.
The projectile analogy. You've seen constant acceleration before: it's what gravity does near the ground. A ball thrown sideways falls in a parabola, because gravity accelerates it steadily downward while its sideways velocity stays put. An electron entering parallel plates at speed does exactly the same thing, with "down" meaning the direction of . Every projectile formula you know carries over:
After it leaves the plates with sideways velocity , at an angle given by . Past the plates there's no field, so it flies in a straight line.
Where it lands. Its height at the exit is . So the straight exit path, extended backward, crosses the axis exactly at the plates' midpoint, and the spot on a screen a distance past the plates sits at
So you can pretend the electron gets a sudden kick at the middle of the plates and flies straight from there. On a typical tube, most of the deflection actually happens during that field-free drift: the plates set the angle, and the long trip to the screen turns it into distance.
Energy. The field does work (a dot product, the constant-force case of work): only motion along the field counts. Released from rest and moving a distance along the force, a charge gains , so . Crossing deflection plates is different. The electron moves along the field only by its small sideways deflection, so the plates steer it while barely changing its speed.
A common mistake. It's tempting to use for the whole trip to the screen, with the whole flight time, since that's how a thrown ball works. It isn't the same here: the field only exists between the plates. The acceleration lasts just , and after that the path is a straight line. Two more things to watch. Electrons accelerate opposite to , so check your signs. And these formulas are only good below about a tenth of the speed of light, m/s; past that you need relativity.
With a magnetic field instead, the force stays perpendicular to the velocity and the parabolas become circles (Magnetic Force on Moving Charges); crossing electric and magnetic fields builds a velocity selector.
See it
Worked examples
An electron enters the gap between two deflection plates at m/s, moving parallel to them. The plates are 4.0 cm long and the field between them is 20 kN/C, pointing down. A screen sits 12 cm past the plates. How far up the screen does the electron land?
- 1
Acceleration: the force on the electron points up, opposite to , with m/s². Gravity's 9.8 m/s² is irrelevant.
In an electron gun, electrons leave a hot cathode essentially at rest and cross a 1.0 cm gap where the field is N/C. How fast are they going when they reach the anode?
- 1
Work by the field: the force points along the motion the whole way, so J.
Practice
Type your answer and check it. Solve them all to complete the lesson.
An electron starts from rest in a uniform field of 2.0 kN/C. How long does it take to reach m/s, in nanoseconds, to 3 significant figures?
An electron sits in a 10 kN/C field. Roughly how does the electric force on it compare with its weight?
A proton starts from rest and travels 4.0 cm along a uniform 50 kN/C field. Find its speed, in km/s, to 3 significant figures.
An electron moving at m/s enters a region where a uniform 1.0 kN/C field points in the same direction as its velocity. How far does it travel before it stops, in cm, to 3 significant figures?
An electron enters a pair of deflection plates 5.0 cm long at m/s, moving parallel to them. The field between the plates is 12 kN/C. How far sideways has it been deflected when it leaves, in mm, to 3 significant figures?
An inkjet coder on a bottling line gives an ink drop of mass kg a charge of pC and fires it at 18 m/s between plates 1.2 cm long, where the field is 1.4 MN/C. The bottle's surface is 2.0 cm beyond the plates. How far from the undeflected spot does the drop land, in mm, to 3 significant figures?
An electron enters a region where a uniform 2.0 kN/C field points straight up, so the force on the electron points down, just like gravity. It's moving at m/s at above the horizontal. How far horizontally does it travel before it's back at its starting height, in cm, to 3 significant figures?
An electron enters deflection plates 5.0 cm long at m/s, moving parallel to them, and the 12 kN/C field between them deflects it 2.93 mm sideways by the time it leaves. The field does work only through that sideways displacement, . By what percentage does the electron's kinetic energy increase while it crosses the plates? Give 3 significant figures.
The hardest one here. Get it, and you've got this lesson.
An oscilloscope tube accelerates electrons from rest across a 2.0 cm gap where the field is N/C. They then pass between deflection plates 4.0 cm long with a 10 kN/C field across them, and coast 20 cm to the screen. How far from the center of the screen do they land, in cm, to 3 significant figures? Then think about why the answer doesn't depend on the particle's charge or mass.
Where it's used
Continuous inkjet coders print dates and batch numbers on bottles, cans and eggs by charging each drop and steering it between deflection plates. Electron-beam lithography writes chip patterns with deflected electron beams, and ion implanters steer charged atoms into silicon the same way. Linear accelerators, from hospital radiotherapy machines to particle colliders, push electrons and protons to high energy with strong fields along their path. Recycling plants sort shredded plastics with electrostatic separators, which deflect charged fragments as they fall between high-voltage plates.