Electric Flux
Electric flux counts how much electric field passes through a surface: field strength times area, scaled down when the field hits at a slant. For curved surfaces or fields that change from place to place, you add up over tiny patches, which is a flux integral.
What the symbols mean
- Electric flux
How much field passes through the surface, in N·m²/C.
- Area vector
Its length is the area and it points along the surface's normal. For a closed surface it points outward.
- Angle
Between the field and the normal, not between the field and the surface.
What the symbols mean
- Area element
A tiny patch of the surface written as a vector, n̂ dA.
- Unit normal
Picks which side counts as positive: outward for a closed surface.
Explanation
Electric flux is simply a measure of how much electric field passes through a surface, the way you might measure how much wind blows through a hoop. The word flux is Latin for "flow." Nothing actually flows in an electric field, but field lines threading a surface behave a lot like a flow, so the name stuck. It's good for counting: the next lesson shows that the flux out of a closed surface tells you exactly how much charge is inside. The formula looks technical, but it's three pieces: (how strong the field is), (how big the surface is) and (how squarely the field hits it, 1 head-on and 0 edge-on). It's just "strength times area, adjusted for tilt"; bear with it.
Picture it. Hold that hoop in a steady wind. Face it into the wind and the most air streams through; tilt it and less gets through; turn it edge-on and nothing does. Electric flux is the same bookkeeping for the electric field: it counts how much passes through a surface.
Uniform field, flat surface. Give the surface an area vector , whose length is the area and which points along the surface's normal. Then , in N·m²/C. There are two ways to see the cosine, and they agree:
- only the field's normal component, , goes through; the part along the surface just skims it;
- or keep all of but use the surface's shadow on a plane perpendicular to the field, of area : every field line through the surface also crosses its shadow.
Flux is a signed number. Past the field crosses backward and the flux is negative, so you always have to say which way the normal points. For a closed surface (a sphere, a box, a can) the rule is outward: flux leaving counts as positive and flux entering as negative.
Curved surfaces, changing fields. Chop the surface into small patches , each small enough to be nearly flat with nearly constant on it, and add: . In the limit that's the flux integral from Flux Integrals: parametrize the surface, use for , and integrate.
The calculation that matters most. A point charge sits at the center of a sphere of radius . Its field, from The Electric Field, points straight out along with the same strength everywhere on the sphere, so
Notice that the radius canceled. Think about why: a bigger sphere has more area, , but the field on it is weaker by exactly . In the field-line picture, every line leaving crosses every sphere around it once, so all those spheres catch the same flux. That's the inverse-square law in disguise, and the next lesson turns it into Gauss's Law.
A common mistake. It's tempting to use the angle between and the surface, because that's the angle you can see in a drawing. It's the wrong one: is measured from the normal, and the surface angle gives you where you need . Two smaller slips to watch for: flux entering a closed surface counts as negative, and flux is a plain number, not a vector.
See it
Worked examples
A 30 cm × 20 cm rectangular sensor plate sits in a uniform field of 600 N/C, with its normal at to the field. Find the flux through it.
- 1
Area: m².
The field , with N/(C·m), fills a region of space. Find the net outward flux through the cube m.
- 1
Only the faces and m can carry flux. On the other four, (along ) runs parallel to the face, so .
Practice
Type your answer and check it. Solve them all to complete the lesson.
A flat square of side 10 cm sits in a uniform field of 3.0 kN/C. The field makes a angle with the plane of the square. Find the flux through the square, in N·m²/C.
A uniform field N/C passes through a closed cube of side 0.1 m with its edges along the axes. What is the flux through the face whose outward normal is , and the net flux through the whole cube?
A 5.0 nC point charge sits at the center of a cube. Find the flux through one face of the cube, in N·m²/C, to 3 significant figures.
A hemispherical radar dome of radius 0.20 m sits on flat ground in a uniform vertical field of 2.5 kN/C pointing straight up along the dome's axis. Find the flux through the curved dome, in N·m²/C, to 3 significant figures.
On a fair-weather day the atmosphere's electric field near the ground is about 120 N/C, pointing straight down. Find the magnitude of the flux through a flat 10 m × 8.0 m roof tilted from horizontal, in kN·m²/C, to 3 significant figures.
The field near an electrode is N/C, with coordinates in meters. Find the upward flux through the square m, m in the plane .
In a region of space, N/C, with in meters. Find the net outward flux through the cube m, in N·m²/C.
The hardest one here. Get it, and you've got this lesson.
A 4.0 nC point charge sits on the axis of a flat disk of radius 4.0 cm, 3.0 cm from the disk's center. Find the flux of its field through the disk, in N·m²/C, to 3 significant figures.
Where it's used
Flux is how engineers count what passes through an opening. The power a solar panel collects scales with the flux of sunlight through it, and all, which is why panels track the sun. Capacitive sensors read the flux of a field ending on an electrode, and the charge it induces, times that flux. And every Gauss's-law calculation in high-voltage design (cables, bushings, insulators) starts by adding up over a carefully chosen surface.