Resonance and Filters
At the inductor and capacitor cancel each other out, so a series RLC circuit's impedance drops to just and the current peaks. That's resonance, and says how sharp the peak is. Filters use the same frequency dependence to let some frequencies through and block others; the simplest, an RC low-pass, has .
What the symbols mean
- Resonant frequency
Where ωL = 1/(ωC): the reactances cancel and Z = R.
- Net reactance
Negative (capacitive) below ω₀, positive (inductive) above.
What the symbols mean
- Quality factor
How sharp the resonance is: the peak frequency divided by the bandwidth. Radio tuners have Q in the hundreds.
- Bandwidth
The width of the peak between the half-power frequencies, in rad/s (divide by 2π for hertz).
What the symbols mean
- Transfer function
What the circuit multiplies each input phasor by: its size scales the amplitude and its angle shifts the phase.
- Cutoff frequency
Where |H| = 1/√2 and the output power is halved. It's 1/τ, the reciprocal of the RC time constant.
Explanation
Resonance is simply a circuit responding far more strongly at one frequency than at any other, the way a swing goes highest when you push it in time with its own rhythm. (The word comes from the Latin for "resound".) A filter is a circuit that lets some frequencies through and blocks others, and between them they're how a radio picks out one station and a sensor gets rid of noise. The favorite frequency depends only on (the inductor, which fights fast changes) and (the capacitor, which blocks slow ones); there the two cancel, and the current gets as big as (the resistor) allows. A filter's is just a number between 0 and 1 (how much of each frequency makes it through). It looks like a pile of formulas, but it's one idea used two ways; bear with it.
Tuning a radio. An antenna picks up every station at once, hundreds of signals at different frequencies piled on top of each other. Turning the dial picks out one. Behind the dial is a series RLC circuit whose response is enormous at one frequency and tiny elsewhere, and the dial turns a variable capacitor that moves that frequency.
Resonance, derived. Drive a series RLC circuit with . From the phasors lesson, , so the current amplitude is
The numerator is fixed, and the denominator is smallest when the reactances cancel, , at
Notice that's the same natural frequency the LC circuit rings at on its own. That's no accident. It's the swing again: push in time with its own rhythm and each push adds to the last. At resonance , so the current is in phase with the source and as large as it can be, . Below the capacitor dominates and the current leads; above it the inductor dominates and the current lags.
Voltage magnification. At resonance the inductor's voltage amplitude is , and the capacitor's is the same. The two are opposite in phase, so they cancel around the loop, but each one on its own can be huge. A 1 V signal can put 100 V across the capacitor of a circuit. Radio receivers use that gain, and power engineers fear it, since a resonance at a harmonic of the grid frequency can overload capacitor banks.
Bandwidth and Q, derived. How wide is the peak? We need a fair way to measure it. The average power delivered is , which falls to half its peak where is down by , that is, where the reactance equals :
The positive roots are , so the bandwidth is exactly
and the product is : the resonant frequency is the geometric mean of the half-power frequencies, not their average. The quality factor compares the peak's position with its width. The same measures ringing: a free RLC circuit's envelope decays like , so a struck high-Q circuit rings for about cycles before falling by a factor of .
Where the peak sits. The current, like a spring's velocity, peaks exactly at . The capacitor's voltage follows the charge, like the spring's displacement, and peaks a little below : the practical resonance of mechanical vibrations. For high the difference is negligible.
Filters. Resonance picks out one frequency. More generally, we'd like to describe what a circuit does to every frequency. That's the job of the transfer function : scales the amplitude and shifts the phase. Take an RC voltage divider with the output across the capacitor:
For , : low frequencies pass. For , : ten times the frequency, a tenth of the amplitude. That's a low-pass filter, and its cutoff is where (half power) and the phase shift is . It's no coincidence that is the reciprocal of the RC time constant: a circuit that needs time to respond can't follow wiggles much faster than .
Swap the parts, taking the output across , and : a high-pass filter with the same cutoff. A series RLC circuit with the output across has , which passes a band of width around : a band-pass filter, which is what the radio tuner really is. The first picture further down lets you play with one. Engineers quote gains in decibels, : dB at cutoff and dB for a factor of 10 in amplitude.
A common mistake. Because the cutoff is called the "half-power" point, it's tempting to think there. It isn't: , and it's the power, which goes as , that's halved. Similarly, it's tempting to put halfway between the two half-power frequencies, but it sits at their geometric mean, not their average. And keep and apart: the bandwidth in hertz is .
See it
Worked examples
An AM radio's tuner has a 240 μH coil with 15 Ω of resistance. What capacitance tunes it to a station at 1000 kHz, and what are its and its bandwidth, in kHz?
- 1
rad/s, and gives F pF.
An audio low-pass filter uses kΩ and nF. Find its cutoff frequency, in kHz, and how much it passes at 1 kHz and at 50 kHz.
- 1
rad/s, so kHz, near the top of human hearing.
Practice
Type your answer and check it. Solve them all to complete the lesson.
A series RLC circuit has mH, μF and Ω, driven by a 10 V amplitude source. Find the resonant frequency, in Hz, and the current amplitude at resonance, in mA.
For the same circuit ( mH, μF, Ω), find and the bandwidth, in hertz.
At resonance, what is the voltage amplitude across the capacitor in that circuit, driven at 10 V amplitude, in volts?
A series RLC circuit is driven below its resonant frequency. Which describes it?
You need an RC low-pass filter with a cutoff of 1.0 kHz, using a 4.7 kΩ resistor. What capacitance, in nF?
A vibration sensor's 50 Hz signal arrives mixed with 2.0 kHz switching noise, and passes through an RC low-pass filter with a 200 Hz cutoff. By what factor is each amplitude multiplied? Enter the signal's factor and then the noise's, to 4 decimal places.
A series RLC circuit has H, μF and Ω. Find the two half-power frequencies, in rad/s.
A guitar pedal's input uses a high-pass RC filter, with the output across a 10 kΩ resistor, to block rumble below 80 Hz. What capacitance gives an 80 Hz cutoff, in nF? What fraction of a 40 Hz rumble's amplitude gets through? Give the fraction to 4 decimal places.
The hardest one here. Get it, and you've got this lesson.
A receiver's tuned circuit is a series RLC circuit with the output taken across Ω, a band-pass filter with . It must be centered on 1.00 MHz with a bandwidth of 10.0 kHz. Find , in μH, and , in pF. A second station at 1.02 MHz arrives with the same strength: by what factor is its output amplitude smaller than the tuned station's? Give that factor, at 1.02 MHz, to 4 decimal places.
Where it's used
Resonance and filtering are everywhere signals are. Radio and TV receivers, Wi-Fi chips and phones select channels with resonant circuits and their crystal and acoustic-wave cousins. Every analog-to-digital converter sits behind a low-pass anti-aliasing filter, audio equalizers are banks of band-pass filters, and the RC filter on a microcontroller's input smooths a noisy sensor before it's sampled. Wireless charging pads and MRI coils are tuned to resonance so that a small drive builds large currents, while power engineers hunt down unwanted resonances that let one harmonic of the grid frequency build up dangerous voltages.