Work
Work is force times distance, but only when the force stays the same. When it changes along the way, chop the motion into tiny steps where the force is nearly constant, and add up force times step: .
What the symbols mean
- Force at position x
Newtons (or pounds). The work over a tiny step dx is F(x) dx.
What the symbols mean
- Spring constant
How stiff the spring is: force per unit of stretch.
- Stretch
Distance from the spring's natural length.
Explanation
Work, in physics, is simply the energy it takes to push or lift something some distance. All we're really saying is: push harder, or push farther, and it takes more work. With a constant force that's just force times distance. The formula handles a force that changes: (the force at position ), (a tiny step, short enough that the force barely changes) and (add up force times step over the whole trip). Hooke's law, , is just the force a spring pushes back with: (how stiff the spring is) times (how far you've stretched it).
This is the same move we've made all unit. Area was height times width, until the height changed; then we sliced it into thin rectangles and integrated. Work is force times distance, until the force changes; then we slice the motion into short steps and integrate. On a graph of force against position, the work is literally the area under the curve.
Units: newton-meters (joules) or foot-pounds.
Springs. Stretching a spring takes more force the farther it's stretched, . Find from one measurement, then integrate.
Pumping liquids. Here the force doesn't change, but the distance does. Slice the liquid into thin horizontal layers. Each layer has a weight (density × × volume) and must be lifted a different distance: the layers near the bottom travel farther. Work for a layer = weight × distance lifted; integrate over all the layers.
Cables and chains. Each piece of a hanging chain is lifted a different distance; slice the chain the same way.
See it
Worked examples
A force of 10 N stretches a spring 0.2 m. How much work stretches it 0.5 m from rest?
- 1
First find the stiffness from the one measurement: , so N/m.
A cylindrical tank with radius 2 m and height 5 m is full of water ( kg/m³). How much work pumps it all out over the top?
- 1
Slice the water into thin layers. A layer at height with thickness is a disk of radius 2, so its volume is and its weight is .
Practice
Type your answer and check it. Solve them all to complete the lesson.
How much work stretches a spring with N/m from its natural length to 0.3 m?
A 6 N force stretches a spring 0.1 m. How much work stretches it 0.4 m?
A 20 m chain weighing 5 N/m hangs from a roof. How much work lifts it all to the roof?
Find the work to pump out the tank in the second example (in joules, a multiple of is fine).
A force N moves an object from to m. Find the work.
A kg bucket hangs from a m cable weighing kg per meter, at the bottom of a m well. How much work does it take to winch the bucket to the top? (Use m/s².)
The hardest one here. Get it, and you've got this lesson.
A conical tank stands point-down: m tall with a top radius of m, full of water ( N/m³). How much work does it take to pump all the water out over the top?
Where it's used
Engineers size pumps for water towers, calculate the energy stored in springs and bows, and estimate the work to lift elevator cables, all with .