Inverse Laplace Transforms
To go back from to , you break into pieces that are already in the table and read off each one. Partial fractions and completing the square are the tools that do the breaking.
Explanation
The inverse Laplace transform is simply the trip back: given , find the function it came from. "Inverse" means it undoes the transform, the way subtracting undoes adding. It's what you need at the end of every problem, because when we solve equations with transforms the answer shows up as some . In practice you're just reading the table backwards. The formulas look busy, but they're just three pairs: (comes from ), and the two with on the bottom (come from and , depending on what's on top). There's no nice integral for going back by hand, and rarely looks exactly like a table entry, so most of the work is ordinary algebra that rearranges it until it does. Bear with the algebra; the idea itself is simple.
Partial fractions split a rational function into simple pieces: , which inverts to . This is the same technique you used in calculus to integrate rational functions. Each factor in the denominator turns into an , so the roots of the denominator tell you which exponentials appear.
Irreducible quadratics: complete the square to get , then split the numerator into a multiple of plus a constant. Those two pieces match the cosine and sine entries.
Adjust constants: inverts to . The table wants a on top, so you put one there and pay for it with a out front.
A common mistake. It's tempting to invert as , because the denominator matches. It isn't quite: the table entry is , so goes with . Always check the numerator too, and fix the constant the way we did above.
See it
Worked examples
Find .
- 1
Split the numerator so each piece matches a table entry with : . The first is a cosine and the second a sine.
Practice
Type your answer and check it. Solve them all to complete the lesson.
Find .
Find .
Find .
Find .
Find .
A circuit's current has transform . Find .
The hardest one here. Get it, and you've got this lesson.
Find .
Where it's used
After designing a system in the s-domain, engineers invert the transform to see the actual time response: overshoot, settling time, oscillation.