Linear Systems with Two Variables
A system asks for the values that make several equations true at the same time. Two linear equations are two lines, so the answer is the point where they cross, and substitution and elimination are two ways of finding it without a graph.
What the symbols mean
- Coefficient of x
In the first equation.
- Coefficient of y
In the first equation.
- Constant
The first equation's right side.
Explanation
A system of equations is simply a group of equations that all have to be true at the same time. Here there are two, each a straight line (that's why they're called "linear"), and all we're really asking is which pair of numbers and works in both at once. That's how you answer questions with two unknowns, like how many adult and child tickets were sold. The formula up top looks like a lot of subscripts, but each line is just a straight-line equation: and (how much and count in the first equation) and (what they have to add up to). The little 1s and 2s only tell you which equation a number belongs to. That's all it is.
So far you've solved one equation in one unknown. Here's the key idea for two: if you can get rid of one variable, you're back to that familiar problem. Both methods below are just two ways of doing that.
Substitution. Solve one equation for one variable, then plug that expression into the other equation. Now the other equation has only one unknown. This is easiest when some variable already has coefficient 1, so solving for it doesn't create fractions.
Elimination. Multiply the equations so one variable has opposite coefficients, then add them. Why is that allowed? If two equations are both true, their sum is true too, so adding them can't lose the solution. Choose the multiples well and one variable cancels out.
Three possible outcomes. Think about what two lines can do.
- One solution: the lines cross once.
- No solution: the lines are parallel and never meet. Elimination ends in a false statement like , which is the algebra telling you no point works.
- Infinitely many: both equations are the same line in disguise. Elimination ends in , true but useless, because every point on the line works.
It's always worth checking your answer in both original equations; it takes ten seconds.
See it
Worked examples
Solve , .
- 1
The 's already have opposite coefficients, so just add the equations: , so .
Practice
Type your answer and check it. Solve them all to complete the lesson.
Solve , . Enter , .
Solve , .
Solve , .
How many solutions does , have?
Adult tickets cost $12 and child tickets $8. 30 tickets sold for $300. How many of each? Enter adults, children.
How many liters of 10% acid and of 40% acid should be mixed to make 30 L of 20% acid? Enter the 10% amount, then the 40% amount.
Solve , . Enter , .
The hardest one here. Get it, and you've got this lesson.
For which and does the system , have infinitely many solutions? Enter , then .
Where it's used
Break-even analysis (cost equals revenue), mixing two products to hit a target, and supply meeting demand are two-equation systems.