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Electromagnetism
/
Electrical Engineering
How Electromagnetism is used in Electrical Engineering
Components
C
=
κ
ε
0
A
d
,
Q
=
C
V
,
U
=
1
2
C
V
2
,
E
=
V
d
C = \frac{\kappa\,\varepsilon_0 A}{d}, \qquad Q = CV, \qquad U = \tfrac12 CV^2, \qquad E = \frac{V}{d}
C
=
d
κ
ε
0
A
,
Q
=
C
V
,
U
=
2
1
C
V
2
,
E
=
d
V
Inside a Capacitor: Area, Gap and Energy
Capacitance and stored energy
E&M
EE
Audio
H
(
ω
)
=
1
1
+
j
ω
R
C
,
∣
H
∣
=
1
1
+
(
ω
R
C
)
2
,
ϕ
=
−
arctan
(
ω
R
C
)
,
f
c
=
1
2
π
R
C
H(\omega) = \frac{1}{1 + j\omega RC}, \qquad |H| = \frac{1}{\sqrt{1 + (\omega RC)^2}}, \qquad \phi = -\arctan(\omega RC), \qquad f_c = \frac{1}{2\pi RC}
H
(
ω
)
=
1
+
j
ω
R
C
1
,
∣
H
∣
=
1
+
(
ω
R
C
)
2
1
,
ϕ
=
−
arctan
(
ω
R
C
)
,
f
c
=
2
π
R
C
1
Smoothing a Signal with an RC Filter
Impedance and frequency response
E&M
EE